Adding a nsfw flag to get_from_reddit, fixes #33

This commit is contained in:
Luke Robles 2018-03-13 13:04:09 -07:00
parent 62038bc9bd
commit 0edc87d44b
2 changed files with 20 additions and 10 deletions

View File

@ -1,9 +1,9 @@
import random
import requests
def get_image(boards):
def get_image(boards, nsfw=False):
"""
get_image(boards)
get_image(boards, nsfw=False)
Returns a URL to an image on reddit from a random board in the boards list
as long as it is hosted on one of the domains in the domains list
@ -18,15 +18,25 @@ def get_image(boards):
'i.imgur.com',
'i.redd.it',
'i.reddituploads.com',
'i3.kym-cdn.com',
'imgur.com',
'media.giphy.com',
'my.mixtape.moe',
]
response = requests.get(
"https://reddit.com/r/{}.json?limit=500".format(boards),
headers = {'User-agent':'discord dragon-bot'}
).json()['data']['children']
request_string = "https://reddit.com/r/{}/random.json".format(boards)
image_urls = list(filter(lambda x: x['data']['domain'] in domains, response))
return random.choice(image_urls)['data']['url'].replace('http://', 'https://')
if not nsfw:
# Append this header to the request. Tells the API to only return SFW results
request_string += '?obey_over18=true'
response = requests.get(
request_string,
headers = {'User-agent':'discord dragon-bot'}
).json()[0]['data']['children'][0]
if response['data']['domain'] not in domains:
# If we dont find an approved domain, re-try the request
return get_image(boards, nsfw=nsfw)
return response['data']['url'].replace('http://', 'https://')

View File

@ -4,7 +4,7 @@ import requests
import get_from_reddit
def get_from_danbooru(boards):
def get_from_danbooru(boards, nsfw=True):
"""
get_from_danbooru(boards)
@ -61,5 +61,5 @@ def get_lewd(channel_name):
]
# This is really bad practice but pass boards to get_from_reddit AND danbooru so it doesnt error
return random.choice([get_from_reddit.get_image, get_from_danbooru])(boards=boards)
return random.choice([get_from_reddit.get_image, get_from_danbooru])(boards=boards, nsfw=True)
return 'You can only use this command in NSFW channels'